Wednesday, September 5, 2012

Career Mania 55: GyanCentral - The hub for engineering and law students - IIT-JEE, AIEEE, BITSAT, CLAT, AILET - 2012: Fid the day .... A simple solution to a common problem

Career Mania 55
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GyanCentral - The hub for engineering and law students - IIT-JEE, AIEEE, BITSAT, CLAT, AILET - 2012: Fid the day .... A simple solution to a common problem
Sep 5th 2012, 12:01

GyanCentral - The hub for engineering and law students - IIT-JEE, AIEEE, BITSAT, CLAT, AILET - 2012
The most comprehensive career education and test preparation forums in india.
Fid the day .... A simple solution to a common problem
Sep 5th 2012, 11:27

You dont keep track of the day ?? You dont like checking calendars for knowing the day ?? You like funny stuff ?? ok ok no more suspense .. here is a fun filled method to find out any day in any year in any month Day of the Week: January has 31 days. It means that every date in February will be 3 days later than the same date in January(28 is 4 weeks exactly). The below table is calculated in such a way. Remember this table which will help you to calculate.
January 0
February 3
March 3
April 6
May 1
June 4
July 6
August 2
September 5
October 0
November 3
December 5
Step1: Ask for the Date. Ex: 23rd June 1986 Step2: Number of the month on the list, June is 4. Step3: Take the date of the month, that is 23 Step4: Take the last 2 digits of the year, that is 86. Step5: Find out the number of leap years. Divide the last 2 digits of the year by 4, 86 divide by 4 is 21. Step6: Now add all the 4 numbers: 4 + 23 + 86 + 21 = 134. Step7: Divide 134 by 7 = 19 remainder 1. The reminder tells you the day.
Sunday 0
Monday 1
Tuesday 2
Wednesday 3
Thursday 4
Friday 5
Saturday 6
Answer: Monday

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